-36x^2+169=0

Solution for -36x^2+169=0 equation:

-36x^2+169=0

a = -36; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-36)·169
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-156}{2*-36}=\frac{-156}{-72}
=2+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+156}{2*-36}=\frac{156}{-72}
=-2+1/6
$